Vedic Maths Tutorial 5.

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·@sugandhaseth·
0.000 HBD
Vedic Maths Tutorial 5.
### Hello fellow Steemians! 

Today we will learn about advanced addition of a list of numbers. We have already seen in the previous tutorial how simple was it to add a list of number. We will now extend the same logic to adding list of numbers with multiple digits. We will also learn the balancing rules in order to complete our understanding on addition of list of numbers. 

https://images.pexels.com/photos/374916/pexels-photo-374916.jpeg?auto=compress&cs=tinysrgb&dpr=2&h=750&w=1260

<sub>**Source**: Pexels</sub>

# Advanced Addition - List of Numbers

Let’s see a very simple example of adding a list of numbers with multiple digits.

  4|3|4
5|5|6
  9|8|7
  3|2|3
+8|5|1
-----------
29|23|21

-----------

### We work as follows:

Step 1: Divide the digits into columns, each column consisting of digits at a place. 
Step 2: Apply the same rule of addition that we learn in the last tutorial to each of the individual columns.
Step 3: Write the answer for each column separately. 
Step 4: Apply balancing rule on the individual answers to get the final answer.

Let’s follow each step mentioned above:

**Step 1**: As you can see, I’ve divided each column with |.

**Step 2**: Let’s apply the addition rule we learnt earlier to units’ place digits.
 
1+3 = 4
4+7 = 11 (-)
1+6 = 7
7+4 = 11 (-)

So the answer becomes 21.

Similarly, by applying the same rules to tens and hundreds place, we get answer as 23 and 29 respectively.

**Step 3**: We write the answers in the specific columns.

**Step 4**:Apply the balancing rule. Let’s see how we do that:

29|23|21

We write the last digit as it is. So the answer we have for now is ___1

Next, we add tens digit from the last number to ones digit of the next number i.e. 2+3 = 5. So the answer we have for now is _ _ 5 1

Next, we add tens digit from the last number to ones digit of the next number i.e. 9+2 = 11. So the answer we have for now is _ 1 5 1

*Finally, we use the carry over from above and add it to the first most digit i.e. 1+2 = 3. 
So the final answer becomes **3151**.*

Isn’t this technique way more simpler than the traditional ones we have learnt? I surely found it easier, but yes after a lot of practice.

***Now practice this with multiple sums.***

356	678	512	434	245	756	667	878	289	190	211	123	
  987	  576	  365	  554	  643	  732	  821	  910	  519	  218	  576	  782	
  739	  470	  909	  820	  765	  645	  512	  424	  267	  348	  934	  545	
  495	  076	  721	  908	  678	  365	  534	  948	  258	  534	  747	  867	
+258	+965	+878	+776	+676	+590	+467	+364	+280	+123	+878	+589	


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