https://youtu.be/ETLaLCpGwLI

In this video I go over the derivative of inverse hyperbolic cosine or cosh<sup>-1</sup> (x) and show that it is equal to 1/sqrt(x<sup>2</sup>-1).

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# Derivative of Inverse Hyperbolic Trigonometry: dy/dx cosh<sup>-1</sup>(x)

![Derivative of Inverse Hyperbolic Trig - inverse cosh(x).jpeg](https://files.peakd.com/file/peakd-hive/mes/23x1abit6CMXhUqiiUvqXgnoNf7fw1fYbGWJgxp1cvrpp6zEz9kiHiGFNBomHM5gJADHC.jpeg)

## Derivative of cosh<sup>-1</sup>x

![image.png](https://files.peakd.com/file/peakd-hive/mes/23t8EjqhGGzS8E3vpPt1fhn6mVbFxnKTdMdMVd7RJVQAX3xwx1D6ShbKtVAnWf88j6846.png)

![image.png](https://files.peakd.com/file/peakd-hive/mes/23tHdQDGn4ZhbwJZYKrRa8AKeiox7dXR7PHhJUbEELNQccLpSMZh7xrYaEZqGmHr9Usv1.png)

![image.png](https://files.peakd.com/file/peakd-hive/mes/23tHbr9ykh98b5nuBVvyT5EyPXdhfVYAgemYLXT6ZX3Wz53er84XZyE8uRbnqpaikiQsq.png)